Problems & Puzzles:
Puzzles
Puzzle 228. Sum of twin
primes, a square
Let p & q to be twin primes (q=p+2)
such that the sum of p & q is a square, that is to say, such that p + q =x^{2}
Example p = 17, q = 19, p + q = 36 =
6^{2}
Question: Find the
four earliest titanic p & q twins having such property^{*}.
_____
^{*} Hint: The
last four digits of the earliest titanic p are 7799.
Solution:
Faride Firoozbakht and J. K.
Andersen solved this puzzle.
Faride sent the smaller prime
of the earliest prime:
p1=
100000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000000000000000000000000
000000000000000000000000000000000000004035547918766213409
143725517651500630631615470558308725599978102680556354957
647888154089895525475555728384686970883323297896566371618
048846796405280294448103718577575188283753156232217118620
241083258464603199204322161923387677962200724322044068968
814279448736951000247607913059170052171767482013869497090
860662129497784722507443360087889195705901906846852947317
589502799647198831609727809825063794946341897892861163188
850925128857335975617279386988149030265106919106546335830
9465685383859118461101308257799
She also sent one more solutions.
a=Ceiling[((10^999+1)/2)^(1/2)] p=2(a+n)^21 ,
q=2(a+n)^2+1. If n >= 0 and p & q are primes, then (p,q) is such pair of
twin primes. p1=2(a+451187)^1 (I wrote before). p2=2(a+1004390)^21
***
J. K. Andersen wrote:
First 5 prp solutions:
18*(x+floor(sqrt(5)*10^499/3))^2+/1, for x=150396,
334797, 639583, 905665, 950299. The prp's have not been proved. The
smallest ends with 7799 as the hint says. The solutions were found with my
own sieve to 2^31, and PrimeForm/GW for prp testing.
He added:
The complexity of twin prp's with N digits is near
O(N^4). The earliest 2000digit prp solution:
18*(550423+floor(sqrt(5)*10^999/3))^2+/1
***
