This is a follow-up to the results obtained to
For S(p, 6m) =
p^0&p^1&...&p^(6m-1) Jan van Delden & Emmanuel Vantieghem
proved that S(p, 6m) is always an integer divisible by 3,
for any prime p>3 and for any m>0 value.
What if p=3 and the quantity
of concatenated terms is still 6m?
May S(3,6m) =
3^0&3^1&...^&3^(6m-1) be a prime for some m value?
As both of them stated, in
such a case S(3,6m) is an odd integer never divided by 3, so
it could produce a prime integer.
The search was extended until
666 concatenated terms or 105987 digits
by Jan van Delden and no
was still found (See
Q. Can you extend this search until a