Problems & Puzzles: Puzzles

Puzzle 895. K consecutive quartets of consecutive primes with different ending digit

Vic Bold sent the following nice puzzle:

Find K consecutive quartets of consecutive primes with different ending digit.

He sent the following examples:

For K=1:
11, 13, 17, 19

For K=2:
47, 53, 59, 61
53, 59, 61, 67

For K=5
191, 193, 197, 199
193, 197, 199, 211
197, 199, 211, 223
199, 211, 223, 227
211, 223, 227, 229

 It was for me not very hard to find a larger example;

K=14
2732087209 2732087227 2732087231 2732087263
2732087227 2732087231 2732087263 2732087279
2732087231 2732087263 2732087279 2732087317
2732087263 2732087279 2732087317 2732087321
2732087279 2732087317 2732087321 2732087333
2732087317 2732087321 2732087333 2732087359
2732087321 2732087333 2732087359 2732087447
2732087333 2732087359 2732087447 2732087461
2732087359 2732087447 2732087461 2732087483
2732087447 2732087461 2732087483 2732087489
2732087461 2732087483 2732087489 2732087537
2732087483 2732087489 2732087537 2732087551
2732087489 2732087537 2732087551 2732087563
2732087537 2732087551 2732087563 2732087569

Q. Send your largest example.

 



 


Records   |  Conjectures  |  Problems  |  Puzzles