Problems & Puzzles: Problems

Problem 4.- Fortune's Conjecture

R. F Fortune conjetured that Nk = P - pk# = primes, if P = the least prime bigger than (pk# +1), being pk#= … .pk

As far as I understood, this is a curious procedure to get a safe small prime from several other smaller primes (pk#)and a bigger one (P).

If you try to calculate the "Fortunate" primes you’ll observe that :

  1. you do not produce all the natural prime numbers (i.e. 2, 11, 29, 31, 41, 43, 53, 73, etc.)
  2. sometimes you produce twice the same prime number (i.e. N5 & N8 are 23)
  3. while at first you can easily calculate the Fortunate primes, soon it’s a harder & harder (time consuming) task.

This are the first 20 Fortunate primes : 3, 5, 7, 13, 23,17, 19, 23, 37, 61, 67, 61, 71, 47, 107, 59, 61, 109, 89, 103.

What exactly is the Fortunate procedure ? Is this the first and unique known "mechanical" procedure to produce as many prime number (forget for a moment the difficulties) as you want. Do you have an explanation or a comment for this conjecture?

(Ref. 2, P. 7)


Said el aidi wrote (10/08/2000):

"To tackle the Fortune conjecture, itís necessary and itís enough to show the following difficult conjecture: pi( x+(lnx)1.99 ) > pi(x+1), for x>8 which means that: ę for x>8, there is always a prime between x+1 and  x+(lnx)1.99  Ľ.

Itís a little finer than that conjectured by Schinzel: pi( x+(lnx)2 ) > pi(x)    for x>8

But which link exists between our conjecture and the Fortune one ?. Let us start by supposing  true our conjecture, we obtain for

x =pk# =2*3*5*Ö*pk , k>2 :

pk# +1< P = prime < pk# +(ln(pk#))1.99

i.e 1< Nk = P - pk# < (ln(pk#))1.99

In 1975, Rosser & Schoenfeld showed that : ln(pk#) < 1.001102pk, hence

1 < Nk < (ln(pk#))1.99 < (1.001102pk)1.99 < p2k< p2k+1

( Itís easy to show that  (1.001102)199 < pk  , for k>2 )

Suppose Nk is composite, then it must have a prime factor lesser than pk+1 ( 2, 3, 5, 7, Ö, or pk ). Therefore P = Nk + pk#  is composite, this contradicts the fact that P is prime .Then Nk must be prime. For k= 1, 2 we can checked the validity of the Fortuneís conjecture   by a simple numerical calculation.

I believe that the procedure of Fortune and that of Carl Pomerance  that I generalized (see Problem 2) are the only ones which can existed and which can give primes, but since the time I canít prove that .

The Rosser & Schoenfeld relation is a straight proof & the formal  reference of this work is Rosser, J.B. & Schoenfeld, L. Sharper bounds for Chebyshev functions Teta(x) and PHI(x). Math .Comp., 29, 243-269,1975.

Note: Teta(x) is called the Chebyshevís function, and I used it for x= pk."


Luis RodrŪguez sent (October  2003) the following comment to the Said's contribution:

Dear Mr. Said

I read your heuristic argument in favor of Fortune's Conjecture, but unfortunately I found a difficulty in your Cramer's modification.

Calling Delta = p(n+1) - p(n) , Cramer affirms:

Lim Sup. Delta / (Log(p(n))^2 = 1 . But if we multiply both sides by (Log(p(n))^.0.01

Lim Sup. Delta / (Log(p(n))^1.99 = (Log(p(n))^0.01

In this case there is not limit for n --> infinite.

Besides I suspect that sooner than later that modification  will be contradicted by a counterexample. In 1999 Bertil Nyman was very near with p(n) = 1.693....x 10^15 the actual Delta is 1132 and, your admissible Delta is 1186.




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