Puzzle 1135 Polynomial with consecutive primes such that...
Davide Rotondo sent the following puzzle:
The polynomial n^4 +
29n^2 + 101 produces 19 consecutive primes whose digits do not alternate
parity, for n=1 to 19
The polynomial of
Kazmenko and Trofimov
| -66n^3 + 3845n^2 - 60897n + 251831 |
It produces 46 consecutive primes which I noticed to be peculiar in that
for n ranging from 0 to 21 and from 23 to 45 the prime numbers do not
have alternating parity digits
Q. ARE THERE OTHER POLYNOMIAL THAT
PRODUCE MORE CONSECUTIVE PRIMES
WITH NO ALTERNATE PARITY DIGITS?